Variable Speed of Light Topples Einstein's Relativity
(trop ancien pour répondre)
Pentcho Valev
2017-08-07 17:54:29 UTC
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"In our animation, Zoe turns on the headlights of her space ship. She measures the speed of light from her headlights as c with respect to her. Jasper sees her travelling towards him at (let's say) v. He measures the speed of light from her headlights as c. No, not c+v, but just c. Surely this is counter-intuitive? Maybe even crazy?" http://newt.phys.unsw.edu.au/einsteinlight/jw/module3_weird_logic.htm

Jasper measures the speed of the light from Zoe's headlights as c'=c+v, not c, in violation of Einstein's relativity. Here is why:

Moving Zoe measures the speed of the light from her headlights as c, the frequency as f, and the wavelength as λ=c/f. If Zoe were at rest (relative to Jasper) and did the same measurements, she would obtain exactly the same c, f and λ. This is required by the principle of relativity - if any of the quantities, e.g. the wavelength, had different values at rest and at motion, the principle of relativity would be obviously violated.

So the emitted wavelength is the same at rest and at motion, according to the principle of relativity, and yet Einsteinians fraudulently teach that the wavefronts bunch up (the wavelength gets shorter) in front of a moving light source and spread out (the wavelength gets longer) behind it:

red shift blue shift

Stephen Hawking, "A Brief History of Time", Chapter 3: "Now imagine a source of light at a constant distance from us, such as a star, emitting waves of light at a constant wavelength. Obviously the wavelength of the waves we receive will be the same as the wavelength at which they are emitted (the gravitational field of the galaxy will not be large enough to have a significant effect). Suppose now that the source starts moving toward us. When the source emits the next wave crest it will be nearer to us, so the distance between wave crests will be smaller than when the star was stationary."

The moving source does not emit shorter wavelength - it emits faster light. If the speed of the source is v, the speed of the light relative to the observer is c'=c+v, in violation of Einstein's relativity. The increased frequency established in Doppler measurements is due to the increased speed of the light and represents a straightforward experimental refutation of Einstein's 1905 constant-speed-of-light postulate.

Pentcho Valev
Pentcho Valev
2017-08-08 08:25:11 UTC
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The motion of the light source does not change the wavelength of the emitted light but Einsteinians safely teach the lie because it sounds reasonable - the motion of the source does change the wavelength for waves other than light.

The problem is much more serious when the observer is moving - the idea that the motion of the observer changes the wavelength is downright idiotic. So idiotic that sometimes Einsteinians explicitly reject it and so inadvertently refute Einstein's relativity:

Albert Einstein Institute: "The frequency of a wave-like signal - such as sound or light - depends on the movement of the sender and of the receiver. This is known as the Doppler effect. [...] Here is an animation of the receiver moving towards the source:

Stationary receiver: Loading Image...

Moving receiver: Loading Image...

By observing the two indicator lights, you can see for yourself that, once more, there is a blue-shift - the pulse frequency measured at the receiver is somewhat higher than the frequency with which the pulses are sent out. This time, THE DISTANCES BETWEEN SUBSEQUENT PULSES ARE NOT AFFECTED, but still there is a frequency shift: As the receiver moves towards each pulse, the time until pulse and receiver meet up is shortened. In this particular animation, which has the receiver moving towards the source at one third the speed of the pulses themselves, four pulses are received in the time it takes the source to emit three pulses." [end of quotation]

Let us jump into the moving receiver's frame of reference. The frequency we measure is

f' = (c + (1/3)c)/d

where d is the distance between subsequent pulses. The speed of the pulses relative to us is, accordingly,

c' = df' = (4/3)c = 400000 km/s,

in violation of Einstein's relativity.

Einsteinians may wish to introduce relativistic corrections (time dilation), in an attempt to save Divine Albert's Divine Theory. The effect would be small and, to their surprise, in the unfavorable direction. The speed of the moving receiver is (1/3)c so gamma is 1.05. Accordingly, the corrected f' is (1.05)*(4/3) s^(-1) and the corrected c' is (1.05)*(400000) km/s. Einstein's relativity is even more violated.

Pentcho Valev
Pentcho Valev
2017-08-08 20:01:13 UTC
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When the observer starts moving towards the light source with speed v, the frequency he measures shifts from f=c/λ to f'=(c+v)/λ=f(1+v/c):

"The Doppler effect - changes in frequencies when sources or observers are in motion - is familiar to anyone who has stood at the roadside and watched (and listened) to the cars go by. It applies to all types of wave, not just sound. [...] Moving Observer. Now suppose the source is fixed but the observer is moving towards the source, with speed v. In time t, ct/λ waves pass a fixed point. A moving point adds another vt/λ. So f'=(c+v)/λ."

"Now let's see what this does to the frequency of the light. We know that even without special relativity, observers moving at different velocities measure different frequencies. (This is the reason the pitch of an ambulance changes as it passes you it doesn't change if you're on the ambulance). This is called the Doppler shift, and for small relative velocity v it is easy to show that the frequency shifts from f to f(1+v/c) (it goes up heading toward you, down away from you). There are relativistic corrections, but these are negligible here."

This mean that the speed of the light relative to the observer shifts from c to c'=c+v, in violation of Einstein's relativity:

"Let's say you, the observer, now move toward the source with velocity vo. You encounter more waves per unit time than you did before. Relative to you, the waves travel at a higher speed: v'=v+vo. The frequency of the waves you detect is higher, and is given by: f'=v'/λ=(v+vo)/λ."

"vo is the velocity of an observer moving towards the source. This velocity is independent of the motion of the source. Hence, the velocity of waves relative to the observer is c + vo. [...] The motion of an observer does not alter the wavelength. The increase in frequency is a result of the observer encountering more wavelengths in a given time."

Pentcho Valev